Question -
Answer -
Given,
50 circular plateseach with diameter 14 cm
Radius of circularplates = 7cm
Thickness of plates =0.5 cm
As these plates areone above the other, the total thickness of all the plates = 0.5 x 50 = 25 cm
So, the total surfacearea of the right circular cylinder formed = 2πr × h + 2πr2
= 2πr (h + r)
= 2(22/7) x 7 x (25 +7)
= 2 x 22 x 32 = 1408cm2
Therefore, the totalsurface area of the cylinder is 1408 cm2