Question -
Answer -
Given,
2.2 dm3 ofbrass is to be drawn into a cylindrical wire of Diameter = 0.25 cm
So, radius of the wire(r) = d/2
= 0.25/2 = 0.125*10-2 cm
Now, 1 cm = 0.01 m
So, 0.1cm = 0.001 m
Let the length of thewire be (h)
We know that,
Volume of the cylinder= πr2h
It’s understood that,
Volume of cylindricalwire = Volume of brass of 2.2 dm3
h = 448 m
Therefore, the lengthof the cylindrical wire drawn is 448 m