Question -
Answer -
Since either coin can turn up Head (H) or Tail (T), are thepossible outcomes.
But, now three coin is tossed so the possible sample spacecontains,
S = {HHH, HHT, HTH, THH, TTH, HTT, TTT, THT}
Where s is sample space and here n(S) = 8
(i) 3 heads
Let us assume ‘A’ be the event of getting 3 heads
n(A)= 1
∴P(A) = n(A)/n(S)
= 1/8
(ii) 2 heads
Let us assume ‘B’ be the event of getting 2 heads
n (A) = 3
∴P(B) = n(B)/n(S)
= 3/8
(iii) at least 2 heads
Let us assume ‘C’ be the event of getting at least 2 head
n(C) = 4
∴P(C) = n(C)/n(S)
= 4/8
= ½
(iv) at most 2 heads
Let us assume ‘D’ be the event of getting at most 2 heads
n(D) = 7
∴P(D) = n(D)/n(S)
= 7/8
(v) no head
Let us assume ‘E’ be the event of getting no heads
n(E) = 1
∴P(E) = n(E)/n(S)
= 1/8
(vi) 3 tails
Let us assume ‘F’ be the event of getting 3 tails
n(F) = 1
∴P(F) = n(F)/n(S)
= 1/8
(vii) Exactly two tails
Let us assume ‘G’ be the event of getting exactly 2 tails
n(G) = 3
∴P(G) = n(G)/n(S)
= 3/8
(viii) no tail
Let us assume ‘H’ be the event of getting no tails
n(H) = 1
∴P(H) = n(H)/n(S)
= 1/8
(ix) at most two tails
Let us assume ‘I’ be the event of getting at most 2 tails
n(I) = 7
∴P(I) = n(I)/n(S)
= 7/8