Question -
Answer -
Let us assume that 1, 2, 3, 4, 5 and 6 are the possible outcomes when the die is thrown.
So, the sample space S = {(1, 1), (1, 2), (1, 3), (1, 4),(1, 5), (1, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5),(6, 6)}
Then, n(S) = 12
(i) Let us assume тАШPтАЩ be the event having sum of numbers as3.
P = {(1, 2)},
Then, n (P) = 1
P(Event) = Number of outcomes favorable to event/ Totalnumber of possible outcomes
тИ┤P(P) = n(P)/n(S)
= 1/12
(ii) Let us assume тАШQтАЩ be the event having sum of number as12.
Then Q = {(6, 6)}, n (Q) = 1
P(Event) = Number of outcomes favorable to event/ Totalnumber of possible outcomes
тИ┤P(Q) = n(Q)/n(S)
= 1/12