Question -
Answer -
Given:
The word ‘MUMBAI’
There are 6 letters inthe word ‘MUMBAI’ out of which 2 are M’s and the rest all are distinct.
So let us considerboth M’s together as one letter, the remaining 5 letters can be arranged in 5!Ways.
Total number ofarrangements = 5!
= 5×4×3×2×1
= 120
Hence, a total numberof words formed during the arrangement of letters of word MUMBAI such that allM’s remains together equals to 120.