The Total solution for NCERT class 6-12
There are 9 (i.epowers 3 + 2 + 4 = 9) objects in the expression a3 b2 c4 and there are 3 a’s, 2 b’s, 4c’s
So by using theformula,
n!/ (p! × q! × r!)
total number ofarrangements = 9! / (3! 2! 4!)
= [9×8×7×6×5×4×3×2×1]/ (3×2×1×2×1×4×3×2×1)
= 7×6×5×3×2×1
= 1260