Question -
Answer -
It is given that the total number of red balls= 5
Let the total number of blue balls = x
So, the total no. of balls = x+5
P(E) = (Number of favourable outcomes/ Totalnumber of outcomes)
∴ P (drawing a blue ball) = [x/(x+5)] ——–(i)
Similarly,
P (drawing a red ball) = [5/(x+5)] ——–(i)
From equation (i) and (ii)
x = 10
So, the total number of blue balls = 10