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Question -

It is given that ina group of 3 students, the probability of 2 students not having the samebirthday is 0.992. What is the probability that the 2 students have the samebirthday?



Answer -

Let the event wherein 2 students having thesame birthday be E

Given, P(E) = 0.992

We know,

P(E)+P(not E) = 1

Or, P(not E) = 1–0.992 = 0.008

The probability that the 2 students have the same birthday is0.008

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