The Total solution for NCERT class 6-12
Let us consider C1 =30o C
And C2 =35o
We know, F = 9/5C + 32
F1 =9/5 C1 + 32
= 9/5 ├Ч 30 + 32
= 9 ├Ч 6 + 32
= 54 + 32
= 86o F
Now,
F2 =9/5 C2 + 32
= 9/5 ├Ч 35 + 32
= 9 ├Ч 7 + 32
= 63 + 32
= 95o F
тИ┤ The range oftemperature of the solution in degree Fahrenheit is 86┬░ F and 95┬░ F.