Question -
Answer -
It is given that CQ : QP= 3: 1 and Area (PBQ) = 10 cm2
Let CQ = x and QP = 3x
We need to find area ofthe parallelogram ABCD.
From the figure,
Area (PBQ) = 
And,
Area (BQC) = 
Now, let H be theperpendicular distance between AP and CD. Therefore,
Area (PCB) = 
…… (1)
Thus the area of theparallelogram ABCD is,
Area (ABCD) = AB × H
⇒ Area (ABCD) = 2BP × H
From equation (1), weget
Area (ABCD) = 4 × 30 =120 cm2
Hence, the area of theparallelogram ABCD is 120 cm2.