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Question -

The following distribution shows the daily pocket allowance of childrenof a locality. The mean pocket allowance is Rs 18. Find the missing frequencyf.



Answer -


Daily Pocket Allowance(in c)

11-13

13-15

15-17

17-19

19-21

21-23

23-35

Number of children

7

6

9

13

f

5

4


Solution:

To find out themissing frequency, use the mean formula.

Here, the value ofmid-point (xi)┬а mean┬аx╠Д┬а= 18

┬а

Class interval

Number of children (fi)

Mid-point (xi)

┬а┬а┬а fixi┬а┬а┬а┬а

11-13

7

12

84

13-15

6

14

84

15-17

9

16

144

17-19

13

18 = A

234

19-21

f

20

20f

21-23

5

22

110

23-25

4

24

96

Total

fi┬а= 44+f

Sum fixi┬а= 752+20f

The mean formula is

Mean = x╠Д = тИСfixi┬а/тИСfi┬а=(752+20f)/(44+f)

Now substitute thevalues and equate to find the missing frequency (f)

тЗТ 18 = (752+20f)/(44+f)

тЗТ 18(44+f) = (752+20f)

тЗТ 792+18f = 752+20f

тЗТ 792+18f = 752+20f

тЗТ 792 тАУ 752 = 20f тАУ 18f

тЗТ 40 = 2f

тЗТ f = 20

So, the missingfrequency, f = 20.

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