Question -
Answer -
Given: AB = 7 cm, BC = 8 cm, AC = 9 cm
In ∆ABC,
In a ΔABC, D, E and F are, respectively, the mid points of BC, CA and AB.
According to Midpoint Theorem:
EF = 1/2BC, DF = 1/2 AC and DE = 1/2 AB
Now, Perimeter of ∆DEF = DE + EF + DF
= 1/2 (AB + BC + AC)
= 1/2 (7 + 8 + 9)
= 12
Perimeter of ΔDEF = 12cm