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Question -

ABC is a triangle and through A, B, C lines are drawn parallel to BC, CA and AB respectively intersecting at P, Q and R. Prove that the perimeter of ΔPQR is double the perimeter of ΔABC.



Answer -

We have   as follows:
 
Through A,B and C lines are drawn parallel to BC,CA and AB respectively intersecting at P,Q and R respectively.
We need to prove that perimeter of   is double the perimeter of  .
 and  
Therefore,   is a parallelogram.
Thus,  
Similarly,
  is a parallelogram.
Thus,  
Therefore,
Then, we can say that A is the mid-point of QR.
Similarly, we can say that B and C are the mid-point of PR and PQ respectively.
In  , 
Theorem states, the line drawn through the mid-point of any one side of a triangle is parallel to the another side, intersects the third side at its mid-point.
Therefore,  
 
Similarly,
 
  
Perimeter of  is double the perimeter of  
Hence proved.


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