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Question -

ABCD is a rhombus, EABF is a straight line such that EA = AB = BF. Prove that ED and FC when produced meet at right angles.



Answer -

Rhombus ABCD is given:
 
We have
 
We need to prove that  
We know that the diagonals of a rhombus bisect each other at right angle.
Therefore,
 , , 
 
In   A and O are the mid-points of BE and BD respectively.
By using mid-point theorem, we get:
 
Therefore,
 
In   A and O are the mid-points of BE and BD respectively.
By using mid-point theorem, we get:
Therefore,
 
Thus, in quadrilateral DOCG,we have:
  and  
Therefore, DOCG is a parallelogram.
Thus, opposite angles of a parallelogram should be equal.
 
Also, it is given that
 
Therefore,
 
Or,
 
Hence proved.


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