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Question -

ABCD is a parallelogram, AD is produced to E so that DE = DC and EC produced meets AB produced in F. Prove that BF = BC



Answer -

ABCD is a parallelogram, AD produced to E such that  .
 
Also , AB produced to F.
We need to prove that  
In  , D and O are the mid-points of AE and AC respectively.
By using Mid-point Theorem, we get:
Since, BD is a straight line and O lies on AC.
And, C lies on EF
 
Therefore,
  …… (i)
Also,  is a parallelogram with  .
Thus,
 
In   and  ,we have:
 
 
 
So, by ASA Congruence criterion, we have:
By corresponding parts of congruence triangles property, we get:
 
From (i) equation, we get:
 
Hence proved.

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