Question -
Answer -
Given: 5x2 –6x + 2 = 0
We shall applydiscriminant rule,
Where, x = (-b ±√(b2 – 4ac))/2a
Here, a = 5, b = -6, c= 2
So,
x = (-(-6) ±√(-62 – 4(5)(2)))/ 2(5)
= (6 ± √(36-40))/10
= (6 ± √(-4))/10
= (6 ± √4(-1))/10
We have i2 =–1
By substituting –1 = i2 inthe above equation, we get
x = (6 ± √4i2)/10
= (6 ± 2i)/10
= 2(3±i)/10
= (3±i)/5
x = 3/5 ± i/5
∴ The roots of thegiven equation are 3/5 ± i/5