The Total solution for NCERT class 6-12
(iii) 7a2 + 14a(iv) -16z + 20z3(v) 20l2m + 30alm(vi) 5x2y – 15xy2(vii) 10a2 – 15b2 + 20c2(viii) -4a2 + 4ab – 4ca(ix) x2yz + xy2z + xyz2(x) ax2y + bxy2 + cxyz
(i) 7x – 42 = 7(x – 6)(ii) 6p – 12q = 6(p – 2q)(iii) 7a2 +14a = 7a(a + 2)(iv) -16z + 20z3 =4z(-4 + 5z2)(v) 20l2m +30alm = 10lm(2l + 3a)(vi) 5x2y – 15xy2 = 5xy(x – 3y)(vii) 10a2 –15b2 +20c2 =5(2a2 –3b2 +4c2)(viii) -4a2 +4ab – 4ca = 4a(-a + b – c)(ix) x2yz + xy2z + xyz2 =xyz(x + y + z)(x) ax2y + bxy2 + cxyz = xy(ax + by + cz)