Question -
Answer -
show that the total rainfall was approximately equivalent to the addition to the normal water of three rivers each 1072 km long, 75 m wide and 3 m deep.
Solution:
From the question, it is clear that
Total volume of 3 rivers = 3×[(Surface area ofa river)×Depth]
Given,
Surface area of a river = [1072×(75/1000)] km
And,
Depth = (3/1000) km
Now, volume of 3 rivers =3×[1072×(75/1000)]×(3/1000)
= 0.72 km3
Now, volume of rainfall = total surface area ×total height of rain
= 9.7 km3
For the total rainfall was approximatelyequivalent to the addition to the normal water of three rivers, the volume ofrainfall has to be equal to volume of 3 rivers.
But, 9.7 km3 ≠ 0.72 km3
So, the question statement is false.