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Question -

Suppose X has a binomial distribution B (6, ½)  . Show that X = 3 is the most likely outcome.
(Hint: P(X = 3) is the maximum among all P(xi), xi = 0,1,2,3,4,5,6)



Answer -

Given X is any randomvariable whose binomial distribution is B (6, ½)

Thus, n = 6 and p = ½

q = 1 – p = 1 – ½ = ½

Thus, P(X = x) = nCqn-x px,where x = 0, 1, 2 …n

It can be clearlyobserved that P(X = x) will be maximum if 6cx willbe maximum.

6cx = 6c6 =1

6c1 = 6c5 =6

6c2 = 6c4 =15

6c3 = 20

Hence we can clearlysee that 6c3 is maximum.

for x = 3, P(X = x)is maximum.

Hence, proved that themost likely outcome is x = 3.

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