Question -
Answer -
B. 2
Explanation:
Given a die havingwritten 1 on three faces, 2 on two faces and 5 on one face.
Let X be the randomvariable representing a number on given die.
Then X can take anyvalue of 1, 2 or 5.
The total numbers issix.
Now
P(X = 1) = 3/6 = ½
P(X = 2) = 1/3
P(X = 5) = 1/6
Hence, the requiredprobability distribution is,
| X | 1 | 2 | 5 |
| P (X) | 1/2 | 1/3 | 1/6 |
Therefore Expectationof X E(X):
