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Question -

Find the probability distribution of
(i) number of heads in two tosses of a coin.

(ii) Number of tails in the simultaneous tosses of three coins.

(iii) Number of heads in four tosses of a coin.



Answer -

(i)

Given a coin is tossedtwice.

Hence, the samplespace of the experiment is S = {HH, HT, TH, TT}

X represents thenumber of heads.

 X (HH) = 2

X (HT) = 1

X (TH) = 1

X (TT) = 0

Therefore, X is afunction on sample space whose range is {0, 1, 2}.

Thus, X is a randomvariable which can take the values 0, 1 or 2.

As we know,

P (HH) = P (HT) = P(TH) = P (TT) = 1/4

P (X = 0) = P (TT) =1/4

P (X = 1) = P (HT) + P(TH) = 1/4 + 1/4 = 1/2

P (X = 2) = P (HH) =1/4

Hence, the requiredprobability distribution is,

X

0

1

2

P (X)

1/4

1/2

1/4


(ii)

Given three coins aretossed simultaneously. Hence, the sample space of the experiment is S = {HHH,HHT, HTH, THH, TTH, THT, HTT, TTT}

X represents thenumber of tails.

As we see, X is afunction on sample space whose range is {0, 1, 2, 3}.

Thus, X is a randomvariable which can take the values 0, 1, 2 or 3.

P (X = 0) = P(HHH) = 1/8

P (X = 1) = P (HHT) +P (HTH) + P (THH) = 1/8 + 1/8 + 1/8 = 3/8

P (X = 2) = P (HTT) +P (THT) + P (TTH) = 1/8 + 1/8 + 1/8 = 3/8

P (X = 3) = P(TTT) = 1/8

Hence, the required probabilitydistribution is,

X

0

1

2

3

P (X)

1/8

3/8

3/8

1/8


(iii)

Given four tosses of acoin.

Hence, the samplespace of the experiment is

S = {HHHH, HHHT, HHTH,HTHH, HTTH, HTHT, HHTT, HTTT, THHH, TTHH, THTH, THHT, THTT, TTHT, TTTH, TTTT}

X represents thenumber of heads.

As we see, X is afunction on sample space whose range is {0, 1, 2, 3, 4}.

Thus, X is a randomvariable which can take the values 0, 1, 2, 3 or 4.

P (X = 0) = P(TTTT) = 1/16

P (X = 1) = P (HTTT) +P (TTTH) + P (THTT) + P (TTHT) = 1/16 + 1/16 + 1/16 + 1/16 = ¼

P(X = 2) = P (HHTT) +P (THHT) + P (TTHH) + P (THTH) + P (HTHT) + P(HTTH)= 1 /16 + 1/16 + 1/16 +1/16 + 1/16 + 1/16 = 6/16 = 3/8

P(X = 3) = P (THHH) +P (HHHT) + P (HTHH) + P (HHTH) = 1/16 + 1/16 + 1/16 + 1/16 = ¼

P(X = 4) = P(HHHH) = 1/16

Hence, the requiredprobability distribution is,

X

0

1

2

3

4

P (X)

1/16

1/4

3/8

1/4

1/16

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