Question -
Answer -
Let E1 bethe event of choosing a two headed coin, E2 be the event ofchoosing a biased coin and E3 be the event of choosing anunbiased coin. Let A be the event that the coin shows head.
Then P (E1)= P (E2) = P (E3) = 1/3
As we a headed coinhas head on both sides so it will shows head.
Also P (A|E1)= P (correct answer given that he knows) = 1
And P (A|E2)= P (coin shows head given that the coin is biased) = 75% = 75/100 = ¾
And P (A|E3)= P (coin shows head given that the coin is unbiased) = ½
Now the probabilitythat the coin is two headed, being given that it shows head, is P (E1|A).
By using Bayes’theorem, we have

