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Probability that A speaks truth is 4/5. A coin is tossed. A reports that a head appears. The probability that actually there was head is
A. 4/5
B. 1/2
C. 1/5
D. 2/5



Answer -

A. 4/5

Explanation:

Let E1┬аbethe event that A speaks truth, E2┬аbe the event that A lies andX be the event that it appears head.

Therefore,┬аP (E1)= 4/5

As E1┬аandE2┬аare the events which are complimentary to each other.

Then P (E1)+ P (E2) = 1

тЗТ┬аP (E2)= 1 тАУ P (E1)

тЗТ┬аP (E2)┬а=1 тАУ 4/5 = 1/5

If a coin is tossed itmay show head or tail.

Hence the probabilityof getting head is 1/2 whether A speaks a truth or A lies.

P (X|E1) =P (X|E2) = ┬╜

Now the probabilitythat actually there was head, give that A speaks a truth is P (E1|X).

By using BayesтАЩtheorem, we have

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