Question -
Answer -
Let E1 bethe event that the driver is a scooter driver, E2 be the eventthat the driver is a car driver and E3 be the event that thedriver is a truck driver. Let A be the event that the person meet with anaccident.
Total number ofdrivers = 2000 + 4000 + 6000 = 12000
Then P (E1)= 2000/12000 = 1/6
P (E2) =4000/12000 = 1/3
P (E3) =6000/12000 = ½
As we a headed coinhas head on both sides so it will shows head.
Also P (A|E1)= P (accident of a scooter driver) = 0.01 = 1/100
And P (A|E2)= P (accident of a car driver) = 0.03 = 3/100
And P (A|E3)= P (accident of a truck driver) = 0.15 = 15/100 = 3/20
Now the probabilitythat the driver is a scooter driver, being given that he met with an accident,is P (E1|A).
By using Bayes’theorem, we have
