Question -
Answer -
Let E1 be theevent that the drawn card is a diamond, E2 be the event that the drawncard is not a diamond and A be the event that the card is lost.
As we know, out of 52cards, 13 cards are diamond and 39 cards are not diamond.
Then P (E1)= 13/52 and P (E2) = 39/52
Now, when a diamondcard is lost then there are 12 diamond cards out of total 51 cards.
Two diamond cards canbe drawn out of 12 diamond cards in 12C2 ways.
Similarly, two diamondcards can be drawn out of total 51 cards in 51C2 ways.
Then probability ofgetting two cards, when one diamond card is lost, is P (A|E1).
Also P (A|E1)=12C2 / 51C2
Now, when not adiamond card is lost then there are 13 diamond cards out of total 51 cards.
Two diamond cards canbe drawn out of 13 diamond cards in 13C2 ways.
Similarly, two diamondcards can be drawn out of total 51 cards in 51C2 ways.
Then probability ofgetting two cards, when card is lost which is not diamond, is P (A|E2).
Also P (A|E2)=13C2 / 51C2
