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Question -

If x = 1 and y = 6 is a solution of the equation 8x – ay + a^2 = 0, find the values of a.



Answer -

Given, ( 1 , 6 ) is a solution of equation 8x – ay + a^2 = 0
Substituting x = 1 and y = 6 in 8x – ay + a^2 = 0, we get
8 x 1 – a x 6 + a^2 = 0
⇒ a^2 – 6a + 8 = 0 (quadratic equation)
Using quadratic factorization
a^2 – 4a – 2a + 8 = 0
a(a – 4) – 2 (a – 4) = 0
(a – 2) (a – 4)= 0
a = 2, 4
Values of a are 2 and 4.

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