The Total solution for NCERT class 6-12
Number of children
Number of Sweets
24
5
(24 – 4) or 20
a
x1y1 = x2y2where x1 = 24, y1 = 5, x2 = 20and y2 = a(let)24 × 5 = 20 × aa = 6Hence, the required number of sweets = 6.