Question -
Answer -
(i) ∠ABC = x°, ∠ACB = 51°, तथा ∠CAD = 107°
ΔACD में, ∠CAD बाह्य कोण है।
अतः ∠CAD = ∠ABC + ∠ACB
107 = x° + 51°
x = 107 – 51
x = 56°
(ii) ΔACD में, ∠A = x°, ∠B = 40°, ∠C = 107°
∠A + ∠B + ∠C = 180°
x + 40 + 107 = 180
x + 147 = 180
x = 180 – 147
x = 33
तथा
x° + 65 + y° = 180°
33 + 65 + y = 180
98 + y = 180
y = 180 – 98
y = 82