Question -
Answer -
Given : In тИЖABC, AD, BE and CF are the altitude of тИЖABC
┬а
To prove : AD + BE + CF < AB + BC + CA
Proof : In right тИЖABD, тИаD = 90┬░
Then other two angles are acute
тИ╡ тИаB < тИаD
тИ┤ AD < AB тАж(i)
Similarly, in тИЖBEC and тИЖABE we can prove thatBE and CF < CA тАж(iii)
Adding (i), (ii), (iii)
AD + BE -t CF < AB + BC + CA