Question -
Answer -
In the figure, AC is the bisector of ∠BAD, AB = 3 cm, AC = 5 cm
In ∆ABC and ∆ADC,
AC = AC (Common)
∠B = ∠D (Each 90°)
∠BAC = ∠DAC (∵ AC is the bisector of ∠A)
∴ ∆ABC ≅ ∆ADC (AAS axiom)
∴ BC = CD and AB = AD (c.p.c.t.)
Now in right ∆ABC,
AC2 = AB2 + BC2
⇒ (5)2 = (3)2 + BC2
⇒25 = 9 + BC2
⇒ BC2 = 25 – 9 = 16 = (4)2
∴ BC = 4 cm
But CD = BC
∴ CD = 4 cm (c)