Question -
Answer -
Given : In an isosceles тИЖABC, AB = AC
and base BC is produced both ways
┬а
To prove : тИаACD = тИаABE
Proof: In тИЖABC,
тИ╡ AB = AC
тИ┤тИаC = тИаB (Angles opposite to equal sides)
тЗТ тИаACB = тИаABC
But тИаACD + тИаACB = 180┬░ (Linear pair)
and тИаABE + тИаABC = 180┬░
тИ┤ тИаACD + тИаACB = тИаABE + тИаABC
But тИаACB = тИаABC (Proved)
тИ┤ тИаACD = тИаABE
Hence proved.