Question -
Answer -
Find:
(i) the total lengthof the silver wire required.
(ii) the area ofeach sector of the brooch.
Diameter (D) = 35 mm
Total number of diameters to be considered= 5
Now, the total length of 5 diameters thatwould be required = 35×5 = 175
Circumference of the circle = 2πr
Or, C = πD = 22/7×35 = 110
Area of the circle = πr2
Or, A = (22/7)×(35/2)2 =1925/2 mm2
(i) Total length of silver wire required = Circumference ofthe circle + Length of 5 diameter
= 110+175 = 185 mm
(ii) Total Number of sectors in the brooch = 10
So, the area of each sector = total area ofthe circle/number of sectors
∴ Area of each sector = (1925/2)×1/10 = 385/4 mm2