Question -
Answer -
Radius of 1st circle = 8 cm(given)
∴ Area of 1st circle = π(8)2 =64π
Radius of 2nd circle = 6 cm(given)
∴ Area of 2nd circle = π(6)2 =36π
So,
The sum of 1st and 2nd circlewill be = 64π+36π = 100π
Now, assume that the radius of 3rd circle= R
∴ Area of the circle 3rd circle = πR2
It is given that the area of the circle 3rd circle= Area of 1st circle + Area of 2nd circle
Or, πR2 = 100πcm2
R2 = 100cm2
So, R = 10cm