The Total solution for NCERT class 6-12
2(a2 + ab) + 3 –ab = 2a2 + 2ab + 3 – ab= 2a2 + 2ab – ab + 3= 2ab + ab + 3Putting, a = 5 and b = -3, we get= 2(5)2 + (5)(-3) + 3= 2 × 25 – 15 + 3= 50 – 15 + 3= 53 – 15 = 38Hence, the required value = 38.