MENU
Question -

Find the vector and Cartesian equations of the planes
(a) that passes through the point (1, 0, –2) and the normal to the plane is
 
(b) that passes through the point (1,4, 6) and the normal vector to the plane is
  



Answer -


x – 1 – 2y + 8 + z – 6= 0

x – 2y + z + 1 = 0

x – 2y + z = -1

The requiredCartesian equation of the plane is x – 2y + z = -1

x – 1 – 2y + 8 + z – 6= 0

x – 2y + z + 1 = 0

x – 2y + z = -1

The requiredCartesian equation of the plane is x – 2y + z = -1

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×