Question -
Answer -
Given:
The plane 2x + y – z =5
Let us express theequation of the plane in intercept form
x/a + y/b + z/c = 1
Where a, b, c are theintercepts cut-off by the plane at x, y and z axes respectively.
2x + y – z =5 …. (1)
Now divide both thesides of equation (1) by 5, we get
2x/5 + y/5 – z/5 = 5/5
2x/5 + y/5 – z/5 = 1
x/(5/2) + y/5 + z/(-5)= 1
Here, a = 5/2, b = 5and c = -5
∴ The interceptscut-off by the plane are 5/2, 5 and -5.