Question -
Answer -
Given:
The points are (1, 1,-1), (6, 4, -5), (-4, -2, 3).
Let,
= 1(12 – 10) – 1(18 –20) -1 (-12 + 16)
= 2 + 2 – 4
= 0
Since, the value ofdeterminant is 0.
∴ The points arecollinear as there will be infinite planes passing through the given 3 points.
(b) (1, 1, 0), (1, 2, 1),(–2, 2, –1)
