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Question -

Find the values of p so that the lines
   are at right angles.



Answer -


So the directionratios of the lines are

-3, 2p/7, 2 and -3p/7,1, -5

Now, as both the linesare at right angles,

So, a1a2 +b1b2 + c1c2 = 0

(-3) (-3p/7) + (2p/7)(1) + 2 (-5) = 0

9p/7 + 2p/7 – 10 = 0

(9p+2p)/7 = 10

11p/7 = 10

11p = 70

p = 70/11

The value of p is70/11

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