The Total solution for NCERT class 6-12
Radius of the circular sheet = 4 cm∴ Area =πr2 = π × 4 × 4 = 16π cm2Radius of the circle to be removed = 3 cm∴ Areaof sheet removed = πr2 = 9π cm2Area of the remaining sheet= (16π – 9π) cm2 = 7π cm2= 7 × 3.14 cm2 = 21.98 cm2Hence, the required area = 21.98 cm2.