The Total solution for NCERT class 6-12
Diameterof the flower bed = 66 m .тИ┤ Radius=┬а66┬а=33 mLet r1┬а= 33 mWidth of the path = 4 mRadius of the flower bed included path= 33 m + 4 m = 37mLet r2┬а= 37mArea of the circular path =┬а
= 3.14 (372тАУ 332)= 3.14 ├Ч (37 + 33) (37 тАУ 33) [Y a2┬атАУb2┬а= (a + b)(a-b)]= 3.14 ├Ч 70 ├Ч 4 = 879.20 m2Hence, the required area = 879.20 m2