The Total solution for NCERT class 6-12
(i)From Jyoti’s diagram:Area of the pentagonal shape = Area of trapezium ABCD + Area of trapezium ADEF= 2 × Area of trapezium ABCD= 2 × 1 (a+ b) × h= (15 + 30) × 7.5= 45 × 7.5= 337.5 m2(ii) From Kavita’s diagram:Area of the pentagonal shape = Area of ∆ABE + Area of square BCDE= 1 ×b × h + 15 × 15= 1 ×15 × 15 + 225= 112.5 + 225= 337.5 m2Yes, we can also find the other way to calculate the area of the givenpentagonal shape.Join CE to divide the figure into two parts, i.e., trapezium ABCE and righttriangle EDC.Area of ABCDE = Area of ∆EDC + Area of square ABCE