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Question -

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.




Answer -

Area of the field = area of ∆ABD + area of ∆BCD
 
= 1/2 × b × h + 1/2 × b × h
= 1/2 × 24 × 13 + 1/2 × 24 × 8
= 12 × 13 + 12 × 8
= 12 × (13 + 8)
= 12 × 21
= 252 m2
Hence, the required area of the field = 252 m2.

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