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Question -

Length of the fence of a trapezium-shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.



Answer -

Given:
AB + BC + CD + DA = 120 m .
BC = 48 m, CD = 17 m, AD = 40 m
AB = 120 m – (48 m + 17 m + 40 m) = 120 – 105 m = 15 m
Area of the trapezium ABCD = 1/2 × (BC + AD) × AB
= 1/2 × (48 + 40) × 15
= 1/2 × 88 × 15
= 44 × 15 = 660 m2.
Hence, the required area = 660 m2

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