Question -
Answer -
The given equation is 49y2 – 16x2 = 784.
It can be written as 49y2 – 16x2 = 784
On comparing equation (1) with the standardequation of hyperbola i.e.,
, we obtain a =4 and b = 7.
We know that a2 + b2 = c2.
Therefore,
The coordinates of thefoci are
.
The coordinates of thevertices are (0, ±4).
Length of latus rectum