Question -
Answer -
We know that the vertex is (0, 0) and the parabola is symmetricabout the y-axis.
The equation of the parabola is either of the from x2 = 4ay or x2 =-4ay.
Given that the parabola passes through point (5, 2), which liesin the first quadrant.
So, the equation of the parabola is of the form x2 = 4ay, while point (5, 2) mustsatisfy the equation x2 = 4ay.
Then,
52 = 4a(2)
25 = 8a
a = 25/8
Thus, the equation of the parabola is
x2 = 4 (25/8)y
x2 = 25y/2
2x2 = 25y
∴ Theequation of the parabola is 2x2 =25y