Question -
Answer -
We know that the vertex is (0, 0) and the parabola is symmetricabout the y-axis.
The equation of the parabola is either of the from x2┬а= 4ay or x2┬а=-4ay.
Given that the parabola passes through point (5, 2), which liesin the first quadrant.
So, the equation of the parabola is of the form x2┬а= 4ay, while point (5, 2) mustsatisfy the equation x2┬а= 4ay.
Then,
52┬а= 4a(2)
25 = 8a
a =┬а25/8
Thus, the equation of the parabola is
x2┬а= 4 (25/8)y
x2┬а= 25y/2
2x2┬а= 25y
тИ┤ Theequation of the parabola is 2x2┬а=25y