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Question -

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30┬░. Determine all the angles of the triangle.



Answer -

Let each of the two equal angles = x
Then third angle = x + 30┬░
But sum of the three angles of a triangle is 180┬░
тИ┤ x + x + x + 30┬░ = 180┬░
тЗТ 3x + 30┬░ = 180┬░
тЗТ3x = 150┬░ тЗТx =┬а┬а= 50┬░
тИ┤ Each equal angle = 50┬░
and third angle = 50┬░ + 30┬░ = 80┬░
тИ┤ Angles are 50┬░, 50┬░ and 80┬░

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