MENU
Question -

आकृति 11.40 में 0 वृत्त का केन्द्र है। ∠AEB= 130° और ∠EBC=20°, तो ∠BDA का मान ज्ञात कीजिए।



Answer -

∠ AEB +∠ BEC = 180°
130° +∠ BEC = 180°
∠ BEC = 180° – 130° = 50°
∆ BEC में, 2 ECB +∠ BEC +∠ EBC = 180°
∠ ECB + 50° +20° = 180°
∠ACB =∠ ECB = 180° – 70° = 110°
∠ BDA =∠ ACB = 110°

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×