Question -
Answer -
Given:
The equation of line is x – 7y + 5 = 0
So, y = 1/7x + 5/7 [which is of the form y = mx + c, where mis the slope of the given line.]
Slope of the given line is 1/7
Slope of the line perpendicular to the line having slope mis -1/m
Slope of the line perpendicular to the line having a slopeof 1/7 is -1/(1/7) = -7
So, the equation of line with slope -7 and x intercept 3 isgiven by y = m(x – d)
y = -7 (x – 3)
y = -7x + 21
7x + y = 21
∴ The equation is 7x + y = 21