MENU
Question -

Find equation of the line parallel to the line 3x − 4y + 2 = 0 and passing through the point (–2, 3).



Answer -

Given:

The line is 3x – 4y + 2 = 0

So, y = 3x/4 + 2/4

= 3x/4 + ½

Which is of the form y = mx + c, where m is the slope of thegiven line.

The slope of the given line is 3/4

We know that parallel line have same slope.

 Slope of other line = m = 3/4

Equation of line having slope m and passing through (x1,y1) is given by

y – y1 = m (x – x1)

 Equation of line having slope 3/4 and passing through(-2, 3) is

y – 3 = ¾ (x – (-2))

4y – 3 × 4 = 3x + 3 × 2

3x – 4y = 18

 The equation is 3x – 4y = 18

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×